Probability of Getting 7 Heads in 8 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 7 Heads in 8 coin tosses.

P(A) = 9/256 = 0.04

The ratio of successful events A = 9 to the total number of possible combinations of a sample space S = 256 is the probability of 7 heads in 8 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 7 heads, if a coin is tossed eight times or 8 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHHTTT, HHHHTHHH, HHHHTHHT,    .    .    .    .    .    .    ,TTTTTHTT, TTTTTTHH, TTTTTTHT, TTTTTTTH, TTTTTTTT}

S = 256

step 2 Find the expected or successful events A
A = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHTHH, HHHHTHHH, HHHTHHHH, HHTHHHHH, HTHHHHHH, THHHHHHH}

A = 9

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 9/256

= 0.04
P(A) = 0.04

0.04 is the probability of getting 7 Heads in 8 tosses.