Probability of Getting 6 Heads in 8 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 6 Heads in 8 coin tosses.

P(A) = 37/256 = 0.14

The ratio of successful events A = 37 to the total number of possible combinations of a sample space S = 256 is the probability of 6 heads in 8 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 6 heads, if a coin is tossed eight times or 8 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHHTTT, HHHHTHHH, HHHHTHHT,    .    .    .    .    .    .    ,TTTTTHTT, TTTTTTHH, TTTTTTHT, TTTTTTTH, TTTTTTTT}

S = 256

step 2 Find the expected or successful events A
A = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHTHHH, HHHHTHHT, HHHHTHTH, HHHHTTHH, HHHTHHHH, HHHTHHHT, HHHTHHTH, HHHTHTHH, HHHTTHHH, HHTHHHHH, HHTHHHHT, HHTHHHTH, HHTHHTHH, HHTHTHHH, HHTTHHHH, HTHHHHHH, HTHHHHHT, HTHHHHTH, HTHHHTHH, HTHHTHHH, HTHTHHHH, HTTHHHHH, THHHHHHH, THHHHHHT, THHHHHTH, THHHHTHH, THHHTHHH, THHTHHHH, THTHHHHH, TTHHHHHH}

A = 37

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 37/256

= 0.14
P(A) = 0.14

0.14 is the probability of getting 6 Heads in 8 tosses.