Probability of Getting 8 Heads in 9 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 8 Heads in 9 coin tosses.

P(A) = 10/512 = 0.02

The ratio of successful events A = 10 to the total number of possible combinations of a sample space S = 512 is the probability of 8 heads in 9 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 8 heads, if a coin is tossed nine times or 9 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHHH, HHHHHHHHT, HHHHHHHTH, HHHHHHHTT, HHHHHHTHH, HHHHHHTHT, HHHHHHTTH, HHHHHHTTT, HHHHHTHHH, HHHHHTHHT,    .    .    .    .    .    .    ,TTTTTTHTT, TTTTTTTHH, TTTTTTTHT, TTTTTTTTH, TTTTTTTTT}

S = 512

step 2 Find the expected or successful events A
A = {HHHHHHHHH, HHHHHHHHT, HHHHHHHTH, HHHHHHTHH, HHHHHTHHH, HHHHTHHHH, HHHTHHHHH, HHTHHHHHH, HTHHHHHHH, THHHHHHHH}

A = 10

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 10/512

= 0.02
P(A) = 0.02

0.02 is the probability of getting 8 Heads in 9 tosses.