Probability of Getting 3 Heads in 4 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 3 Heads in 4 coin tosses.
P(A) = 5/16 = 0.31 for total possible combinations for sample space S = {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT} & successful events for getting at least 3 heads A = {HHHH, HHHT, HHTH, HTHH, THHH} for an experiment consists of four independent events.

The ratio of successful events A = 5 to the total number of possible combinations of a sample space S = 16 is the probability of 3 heads in 4 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 3 heads, if a coin is tossed four times or 4 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}

S = 16

step 2 Find the expected or successful events A
A = {HHHH, HHHT, HHTH, HTHH, THHH}

A = 5

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 5/16

= 0.31
P(A) = 0.31

0.31 is the probability of getting 3 Heads in 4 tosses.