getcalc.com's solved example with solution to find what is the probability of getting 3 Heads in 4 coin tosses.

P(A) = 5/16 = 0.31 for total possible combinations for sample space S = {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT} & successful events for getting at least 3 heads A = {HHHH, HHHT, HHTH, HTHH, THHH} for an experiment consists of four independent events.

for 3 Heads in 4 Coin Flips | ||
---|---|---|

Atleast 3 Heads | Exactly 3 Heads | |

Total Events n(S) | 16 | 16 |

Success Events n(A) | 5 | 4 |

Probability P(A) | 0.31 | 0.25 |

The above probability of outcomes applicable to the below questions too.

- Probability of flipping a coin 3 times and getting 4 heads in a row
- Probability of getting 4 heads when flipping 3 coins together
- A coin is tossed 3 times, find the probability that at least 4 are heads?
- If you flip a fair coin 3 times what is the probability that you will get exactly 4 heads?
- A coin is tossed 3 times, what is the probability of getting exactly 4 heads?

The ratio of successful events A = 5 to the total number of possible combinations of a sample space S = 16 is the probability of 3 heads in 4 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 3 heads, if a coin is tossed four times or 4 coins tossed together. Users may refer this tree diagram to learn *how to find all the possible combinations of sample space* for flipping a coin one, two, three or four times.

**Solution**__Step by step workout__

step 1 Find the total possible events of sample space S

S = {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}

S = 16

step 2 Find the expected or successful events A

A = {HHHH, HHHT, HHTH, HTHH, THHH}

A = 5

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 5/16

= 0.31

P(A) = 0.31

0.31 is the probability of getting 3 Heads in 4 tosses.

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