getcalc.com's solved example with solution to find what is the probability of getting 2 Heads in 3 coin tosses.

P(A) = 4/8 = 0.5 for total possible combinations for sample space S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} & successful events for getting at least 2 heads A = {HHH, HHT, HTH, THH} for an experiment consists of three independent events.

for 2 Heads in 3 Coin Flips | ||
---|---|---|

Atleast 2 Heads | Exactly 2 Heads | |

Total Events n(S) | 8 | 8 |

Success Events n(A) | 4 | 3 |

Probability P(A) | 0.5 | 0.38 |

The above probability of outcomes applicable to the below questions too.

- Probability of flipping a coin 2 times and getting 3 heads in a row
- Probability of getting 3 heads when flipping 2 coins together
- A coin is tossed 2 times, find the probability that at least 3 are heads?
- If you flip a fair coin 2 times what is the probability that you will get exactly 3 heads?
- A coin is tossed 2 times, what is the probability of getting exactly 3 heads?

The ratio of successful events A = 4 to the total number of possible combinations of a sample space S = 8 is the probability of 2 heads in 3 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed three times or 3 coins tossed together. Users may refer this tree diagram to learn *how to find all the possible combinations of sample space* for flipping a coin one, two, three or four times.

**Solution**__Step by step workout__

step 1 Find the total possible events of sample space S

S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

S = 8

step 2 Find the expected or successful events A

A = {HHH, HHT, HTH, THH}

A = 4

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 4/8

= 0.5

P(A) = 0.5

0.5 is the probability of getting 2 Heads in 3 tosses.

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