getcalc.com's solved example with solution to find what is the probability of getting 2 Heads in 3 coin tosses.
P(A) = 4/8 = 0.5 for total possible combinations for sample space S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} & successful events for getting at least 2 heads A = {HHH, HHT, HTH, THH} for an experiment consists of three independent events.
for 2 Heads in 3 Coin Flips | ||
---|---|---|
Atleast 2 Heads | Exactly 2 Heads | |
Total Events n(S) | 8 | 8 |
Success Events n(A) | 4 | 3 |
Probability P(A) | 0.5 | 0.38 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 4 to the total number of possible combinations of a sample space S = 8 is the probability of 2 heads in 3 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed three times or 3 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
S = 8
step 2 Find the expected or successful events A
A = {HHH, HHT, HTH, THH}
A = 4
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 4/8
= 0.5
P(A) = 0.5
0.5 is the probability of getting 2 Heads in 3 tosses.