# Probability of Getting 2 Heads in 5 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 2 Heads in 5 coin tosses.

P(A) = 26/32 = 0.81

for 2 Heads in 5 Coin Flips | ||
---|---|---|

Atleast 2 Heads | Exactly 2 Heads | |

Total Events n(S) | 32 | 32 |

Success Events n(A) | 26 | 10 |

Probability P(A) | 0.81 | 0.31 |

The above probability of outcomes applicable to the below questions too.

- Probability of flipping a coin 2 times and getting 5 heads in a row
- Probability of getting 5 heads when flipping 2 coins together
- A coin is tossed 2 times, find the probability that at least 5 are heads?
- If you flip a fair coin 2 times what is the probability that you will get exactly 5 heads?
- A coin is tossed 2 times, what is the probability of getting exactly 5 heads?

## Atleast 2 Heads in 5 Coin Tosses

The ratio of successful events A = 26 to the total number of possible combinations of a sample space S = 32 is the probability of 2 heads in 5 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed five times or 5 coins tossed together. Users may refer this tree diagram to learn *how to find all the possible combinations of sample space* for flipping a coin one, two, three or four times.

**Solution**__Step by step workout__

step 1 Find the total possible events of sample space S

S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A

A = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, TTHHH, TTHHT, TTHTH, TTTHH}

A = 26

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 26/32

= 0.81

P(A) = 0.81

0.81 is the probability of getting 2 Heads in 5 tosses.

## Exactly 2 heads in 5 Coin Flips

The ratio of successful events A = 10 to total number of possible *combinations* of sample space S = 32 is the probability of 2 heads in 5 coin tosses. Users may refer the below detailed solved example with step by step calculation to learn how to find what is the probability of getting exactly 2 heads, if a coin is tossed five times or 5 coins tossed together.

**Solution :**__Step by step workout__

step 1 Find the total possible combinations of sample space S

S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A

A = {HHTTT, HTHTT, HTTHT, HTTTH, THHTT, THTHT, THTTH, TTHHT, TTHTH, TTTHH}

A = 10

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 10/32

= 0.31

P(A) = 0.31

0.31 is the probability of getting exactly 2 Heads in 5 tosses.