getcalc.com's solved example with solution to find what is the probability of getting 2 Heads in 9 coin tosses.
P(A) = 502/512 = 0.98
for 2 Heads in 9 Coin Flips | ||
---|---|---|
Atleast 2 Heads | Exactly 2 Heads | |
Total Events n(S) | 512 | 512 |
Success Events n(A) | 502 | 36 |
Probability P(A) | 0.98 | 0.07 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 502 to the total number of possible combinations of a sample space S = 512 is the probability of 2 heads in 9 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed nine times or 9 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHHH, HHHHHHHHT, HHHHHHHTH, HHHHHHHTT, HHHHHHTHH, HHHHHHTHT, HHHHHHTTH, HHHHHHTTT, HHHHHTHHH, HHHHHTHHT, . . . . . . ,TTTTTTHTT, TTTTTTTHH, TTTTTTTHT, TTTTTTTTH, TTTTTTTTT}
S = 512
step 2 Find the expected or successful events A
A = {HHHHHHHHH, HHHHHHHHT, HHHHHHHTH, HHHHHHHTT, HHHHHHTHH, HHHHHHTHT, HHHHHHTTH, HHHHHHTTT, HHHHHTHHH, HHHHHTHHT, . . . . . . ,TTTTTHTTH, TTTTTTHHH, TTTTTTHHT, TTTTTTHTH, TTTTTTTHH}
A = 502
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 502/512
= 0.98
P(A) = 0.98
0.98 is the probability of getting 2 Heads in 9 tosses.