getcalc.com's solved example with solution to find what is the probability of getting 2 Heads in 8 coin tosses.
P(A) = 247/256 = 0.96
for 2 Heads in 8 Coin Flips | ||
---|---|---|
Atleast 2 Heads | Exactly 2 Heads | |
Total Events n(S) | 256 | 256 |
Success Events n(A) | 247 | 28 |
Probability P(A) | 0.96 | 0.11 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 247 to the total number of possible combinations of a sample space S = 256 is the probability of 2 heads in 8 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed eight times or 8 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHHTTT, HHHHTHHH, HHHHTHHT, . . . . . . ,TTTTTHTT, TTTTTTHH, TTTTTTHT, TTTTTTTH, TTTTTTTT}
S = 256
step 2 Find the expected or successful events A
A = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHHTTT, HHHHTHHH, HHHHTHHT, . . . . . . ,TTTTHTTH, TTTTTHHH, TTTTTHHT, TTTTTHTH, TTTTTTHH}
A = 247
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 247/256
= 0.96
P(A) = 0.96
0.96 is the probability of getting 2 Heads in 8 tosses.