getcalc.com's solved example with solution to find what is the probability of getting 1 Head in 8 coin tosses.
P(A) = 255/256 = 1
for 1 Head in 8 Coin Flips | ||
---|---|---|
Atleast 1 Head | Exactly 1 Head | |
Total Events n(S) | 256 | 256 |
Success Events n(A) | 255 | 8 |
Probability P(A) | 1 | 0.03 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 255 to the total number of possible combinations of a sample space S = 256 is the probability of 1 head in 8 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 1 head, if a coin is tossed eight times or 8 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHHTTT, HHHHTHHH, HHHHTHHT, . . . . . . ,TTTTTHTT, TTTTTTHH, TTTTTTHT, TTTTTTTH, TTTTTTTT}
S = 256
step 2 Find the expected or successful events A
A = {HHHHHHHH, HHHHHHHT, HHHHHHTH, HHHHHHTT, HHHHHTHH, HHHHHTHT, HHHHHTTH, HHHHHTTT, HHHHTHHH, HHHHTHHT, . . . . . . ,TTTTTHTH, TTTTTHTT, TTTTTTHH, TTTTTTHT, TTTTTTTH}
A = 255
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 255/256
= 1
P(A) = 1
1 is the probability of getting 1 Head in 8 tosses.