# Probability of Getting 2 Heads in 6 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 2 Heads in 6 coin tosses.

P(A) = 57/64 = 0.89

for 2 Heads in 6 Coin Flips
Total Events n(S)6464
Success Events n(A)5715
Probability P(A)0.890.23

The above probability of outcomes applicable to the below questions too.

• Probability of flipping a coin 2 times and getting 6 heads in a row
• Probability of getting 6 heads when flipping 2 coins together
• A coin is tossed 2 times, find the probability that at least 6 are heads?
• If you flip a fair coin 2 times what is the probability that you will get exactly 6 heads?
• A coin is tossed 2 times, what is the probability of getting exactly 6 heads?

## Atleast 2 Heads in 6 Coin Tosses

The ratio of successful events A = 57 to the total number of possible combinations of a sample space S = 64 is the probability of 2 heads in 6 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed fix times or 6 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHH, HHHHHT, HHHHTH, HHHHTT, HHHTHH, HHHTHT, HHHTTH, HHHTTT, HHTHHH, HHTHHT, HHTHTH, HHTHTT, HHTTHH, HHTTHT, HHTTTH, HHTTTT, HTHHHH, HTHHHT, HTHHTH, HTHHTT, HTHTHH, HTHTHT, HTHTTH, HTHTTT, HTTHHH, HTTHHT, HTTHTH, HTTHTT, HTTTHH, HTTTHT, HTTTTH, HTTTTT, THHHHH, THHHHT, THHHTH, THHHTT, THHTHH, THHTHT, THHTTH, THHTTT, THTHHH, THTHHT, THTHTH, THTHTT, THTTHH, THTTHT, THTTTH, THTTTT, TTHHHH, TTHHHT, TTHHTH, TTHHTT, TTHTHH, TTHTHT, TTHTTH, TTHTTT, TTTHHH, TTTHHT, TTTHTH, TTTHTT, TTTTHH, TTTTHT, TTTTTH, TTTTTT}

S = 64

step 2 Find the expected or successful events A
A = {HHHHHH, HHHHHT, HHHHTH, HHHHTT, HHHTHH, HHHTHT, HHHTTH, HHHTTT, HHTHHH, HHTHHT, HHTHTH, HHTHTT, HHTTHH, HHTTHT, HHTTTH, HHTTTT, HTHHHH, HTHHHT, HTHHTH, HTHHTT, HTHTHH, HTHTHT, HTHTTH, HTHTTT, HTTHHH, HTTHHT, HTTHTH, HTTHTT, HTTTHH, HTTTHT, HTTTTH, THHHHH, THHHHT, THHHTH, THHHTT, THHTHH, THHTHT, THHTTH, THHTTT, THTHHH, THTHHT, THTHTH, THTHTT, THTTHH, THTTHT, THTTTH, TTHHHH, TTHHHT, TTHHTH, TTHHTT, TTHTHH, TTHTHT, TTHTTH, TTTHHH, TTTHHT, TTTHTH, TTTTHH}

A = 57

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 57/64

= 0.89
P(A) = 0.89

0.89 is the probability of getting 2 Heads in 6 tosses.

## Exactly 2 heads in 6 Coin Flips

The ratio of successful events A = 15 to total number of possible combinations of sample space S = 64 is the probability of 2 heads in 6 coin tosses. Users may refer the below detailed solved example with step by step calculation to learn how to find what is the probability of getting exactly 2 heads, if a coin is tossed fix times or 6 coins tossed together.

Solution :
Step by step workout
step 1 Find the total possible combinations of sample space S
S = {HHHHHH, HHHHHT, HHHHTH, HHHHTT, HHHTHH, HHHTHT, HHHTTH, HHHTTT, HHTHHH, HHTHHT, HHTHTH, HHTHTT, HHTTHH, HHTTHT, HHTTTH, HHTTTT, HTHHHH, HTHHHT, HTHHTH, HTHHTT, HTHTHH, HTHTHT, HTHTTH, HTHTTT, HTTHHH, HTTHHT, HTTHTH, HTTHTT, HTTTHH, HTTTHT, HTTTTH, HTTTTT, THHHHH, THHHHT, THHHTH, THHHTT, THHTHH, THHTHT, THHTTH, THHTTT, THTHHH, THTHHT, THTHTH, THTHTT, THTTHH, THTTHT, THTTTH, THTTTT, TTHHHH, TTHHHT, TTHHTH, TTHHTT, TTHTHH, TTHTHT, TTHTTH, TTHTTT, TTTHHH, TTTHHT, TTTHTH, TTTHTT, TTTTHH, TTTTHT, TTTTTH, TTTTTT}

S = 64

step 2 Find the expected or successful events A
A = {HHTTTT, HTHTTT, HTTHTT, HTTTHT, HTTTTH, THHTTT, THTHTT, THTTHT, THTTTH, TTHHTT, TTHTHT, TTHTTH, TTTHHT, TTTHTH, TTTTHH}

A = 15

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 15/64

= 0.23
P(A) = 0.23

0.23 is the probability of getting exactly 2 Heads in 6 tosses.