# Probability of Getting 1 Head in 5 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 1 Head in 5 coin tosses.

P(A) = 31/32 = 0.97

for 1 Head in 5 Coin Flips | ||
---|---|---|

Atleast 1 Head | Exactly 1 Head | |

Total Events n(S) | 32 | 32 |

Success Events n(A) | 31 | 5 |

Probability P(A) | 0.97 | 0.16 |

The above probability of outcomes applicable to the below questions too.

- Probability of flipping a coin 1 times and getting 5 head in a row
- Probability of getting 5 head when flipping 1 coins together
- A coin is tossed 1 times, find the probability that at least 5 are head?
- If you flip a fair coin 1 times what is the probability that you will get exactly 5 head?
- A coin is tossed 1 times, what is the probability of getting exactly 5 head?

## Atleast 1 Head in 5 Coin Tosses

The ratio of successful events A = 31 to the total number of possible combinations of a sample space S = 32 is the probability of 1 head in 5 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 1 head, if a coin is tossed five times or 5 coins tossed together. Users may refer this tree diagram to learn *how to find all the possible combinations of sample space* for flipping a coin one, two, three or four times.

**Solution**__Step by step workout__

step 1 Find the total possible events of sample space S

S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A

A = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH}

A = 31

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 31/32

= 0.97

P(A) = 0.97

0.97 is the probability of getting 1 Head in 5 tosses.

## Exactly 1 head in 5 Coin Flips

The ratio of successful events A = 5 to total number of possible *combinations* of sample space S = 32 is the probability of 1 head in 5 coin tosses. Users may refer the below detailed solved example with step by step calculation to learn how to find what is the probability of getting exactly 1 head, if a coin is tossed five times or 5 coins tossed together.

**Solution :**__Step by step workout__

step 1 Find the total possible combinations of sample space S

S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A

A = {HTTTT, THTTT, TTHTT, TTTHT, TTTTH}

A = 5

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 5/32

= 0.16

P(A) = 0.16

0.16 is the probability of getting exactly 1 Head in 5 tosses.