# Probability of Getting 1 Head in 5 Coin Tosses getcalc.com's solved example with solution to find what is the probability of getting 1 Head in 5 coin tosses.

P(A) = 31/32 = 0.97

for 1 Head in 5 Coin Flips
Total Events n(S)3232
Success Events n(A)315
Probability P(A)0.970.16

The above probability of outcomes applicable to the below questions too.

• Probability of flipping a coin 1 times and getting 5 head in a row
• Probability of getting 5 head when flipping 1 coins together
• A coin is tossed 1 times, find the probability that at least 5 are head?
• If you flip a fair coin 1 times what is the probability that you will get exactly 5 head?
• A coin is tossed 1 times, what is the probability of getting exactly 5 head?

## Atleast 1 Head in 5 Coin Tosses

The ratio of successful events A = 31 to the total number of possible combinations of a sample space S = 32 is the probability of 1 head in 5 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 1 head, if a coin is tossed five times or 5 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A
A = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH}

A = 31

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 31/32

= 0.97
P(A) = 0.97

0.97 is the probability of getting 1 Head in 5 tosses.

## Exactly 1 head in 5 Coin Flips

The ratio of successful events A = 5 to total number of possible combinations of sample space S = 32 is the probability of 1 head in 5 coin tosses. Users may refer the below detailed solved example with step by step calculation to learn how to find what is the probability of getting exactly 1 head, if a coin is tossed five times or 5 coins tossed together.

Solution :
Step by step workout
step 1 Find the total possible combinations of sample space S
S = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT}

S = 32

step 2 Find the expected or successful events A
A = {HTTTT, THTTT, TTHTT, TTTHT, TTTTH}

A = 5

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 5/32

= 0.16
P(A) = 0.16

0.16 is the probability of getting exactly 1 Head in 5 tosses. 