# Probability of Getting 1 Head in 3 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 1 Head in 3 coin tosses.

P(A) = 7/8 = 0.88 for total possible *combinations* for sample space S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} & successful events for getting at least 1 head A = {HHH, HHT, HTH, HTT, THH, THT, TTH} for an experiment consists of three independent events.

for 1 Head in 3 Coin Flips | ||
---|---|---|

Atleast 1 Head | Exactly 1 Head | |

Total Events n(S) | 8 | 8 |

Success Events n(A) | 7 | 3 |

Probability P(A) | 0.88 | 0.38 |

The above probability of outcomes applicable to the below questions too.

- Probability of flipping a coin 1 times and getting 3 head in a row
- Probability of getting 3 head when flipping 1 coins together
- A coin is tossed 1 times, find the probability that at least 3 are head?
- If you flip a fair coin 1 times what is the probability that you will get exactly 3 head?
- A coin is tossed 1 times, what is the probability of getting exactly 3 head?

## Atleast 1 Head in 3 Coin Tosses

The ratio of successful events A = 7 to the total number of possible combinations of a sample space S = 8 is the probability of 1 head in 3 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 1 head, if a coin is tossed three times or 3 coins tossed together. Users may refer this tree diagram to learn *how to find all the possible combinations of sample space* for flipping a coin one, two, three or four times.

**Solution**__Step by step workout__

step 1 Find the total possible events of sample space S

S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

S = 8

step 2 Find the expected or successful events A

A = {HHH, HHT, HTH, HTT, THH, THT, TTH}

A = 7

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 7/8

= 0.88

P(A) = 0.88

0.88 is the probability of getting 1 Head in 3 tosses.

## Exactly 1 head in 3 Coin Flips

The ratio of successful events A = 3 to total number of possible combinations of sample space S = 8 is the probability of 1 head in 3 coin tosses. Users may refer the below detailed solved example with step by step calculation to learn how to find what is the probability of getting exactly 1 head, if a coin is tossed three times or 3 coins tossed together.

**Solution :**__Step by step workout__

step 1 Find the total possible combinations of sample space S

S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

S = 8

step 2 Find the expected or successful events A

A = {HTT, THT, TTH}

A = 3

step 3 Find the probability

P(A) = Successful Events/Total Events of Sample Space

= 3/8

= 0.38

P(A) = 0.38

0.38 is the probability of getting exactly 1 Head in 3 tosses.