getcalc.com's solved example with solution to find what is the probability of getting 1 Tail in 3 coin tosses.
P(A) = 7/8 = 0.88 for total possible combinations for sample space S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} & successful events for getting at least 1 tail A = {HHT, HTH, HTT, THH, THT, TTH, TTT} for an experiment consists of three independent events.
for 1 Tail in 3 Coin Flips | ||
---|---|---|
Atleast 1 Tail | Exactly 1 Tail | |
Total Events n(S) | 8 | 8 |
Success Events n(A) | 7 | 3 |
Probability P(A) | 0.88 | 0.38 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 7 to the total number of possible combinations of a sample space S = 8 is the probability of 1 tail in 3 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 1 tail, if a coin is tossed three times or 3 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
S = 8
step 2 Find the expected or successful events A
A = {HHT, HTH, HTT, THH, THT, TTH, TTT}
A = 7
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 7/8
= 0.88
P(A) = 0.88
0.88 is the probability of getting 1 Tail in 3 tosses.