getcalc.com's solved example with solution to find what is the probability of getting 1 Tail in 2 coin tosses.
P(A) = 3/4 = 0.75 for total possible combinations for sample space S = {HH, HT, TH, TT} & successful events for getting at least 1 tail A = {HT, TH, TT} for an experiment consists of two independent events.
for 1 Tail in 2 Coin Flips | ||
---|---|---|
Atleast 1 Tail | Exactly 1 Tail | |
Total Events n(S) | 4 | 4 |
Success Events n(A) | 3 | 2 |
Probability P(A) | 0.75 | 0.5 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 3 to the total number of possible combinations of a sample space S = 4 is the probability of 1 tail in 2 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 1 tail, if a coin is tossed two times or 2 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HH, HT, TH, TT}
S = 4
step 2 Find the expected or successful events A
A = {HT, TH, TT}
A = 3
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 3/4
= 0.75
P(A) = 0.75
0.75 is the probability of getting 1 Tail in 2 tosses.