Probability of Getting 3 Heads in 10 Coin Tosses

getcalc.com's solved example with solution to find what is the probability of getting 3 Heads in 10 coin tosses.

P(A) = 968/1024 = 0.95

The ratio of successful events A = 968 to the total number of possible combinations of a sample space S = 1024 is the probability of 3 heads in 10 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 3 heads, if a coin is tossed ten times or 10 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.

Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHHHH, HHHHHHHHHT, HHHHHHHHTH, HHHHHHHHTT, HHHHHHHTHH, HHHHHHHTHT, HHHHHHHTTH, HHHHHHHTTT, HHHHHHTHHH, HHHHHHTHHT,    .    .    .    .    .    .    ,TTTTTTTHTT, TTTTTTTTHH, TTTTTTTTHT, TTTTTTTTTH, TTTTTTTTTT}

S = 1024

step 2 Find the expected or successful events A
A = {HHHHHHHHHH, HHHHHHHHHT, HHHHHHHHTH, HHHHHHHHTT, HHHHHHHTHH, HHHHHHHTHT, HHHHHHHTTH, HHHHHHHTTT, HHHHHHTHHH, HHHHHHTHHT,    .    .    .    .    .    .    ,TTTTTTHHHH, TTTTTTHHHT, TTTTTTHHTH, TTTTTTHTHH, TTTTTTTHHH}

A = 968

step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 968/1024

= 0.95
P(A) = 0.95

0.95 is the probability of getting 3 Heads in 10 tosses.