58 in Binary

Decimal 58 in binary conversion provides the detailed information on what is the binary equivalent of (58)10, and the step-by-step work for how to convert the decimal (base-10) number 58 to its binary (base-2) equivalent.

(58)10 in binary is equal to:
(58)₁₀ = (?)₂
Perform successive MOD-2 operation for decimal 58, and mark the initial remainder as LSB and the final remainder as MSB as like the below.

58 MOD-2	58 / 2 = 29	Remainder is 0 → LSB
29 MOD-2	29 / 2 = 14	Remainder is 1
14 MOD-2	14 / 2 = 7	Remainder is 0
7 MOD-2	7 / 2 = 3	Remainder is 1
3 MOD-2	3 / 2 = 1	Remainder is 1
1 MOD-2	1 / 2 = 0	Remainder is 1 → MSB

Arrange the remainders from MSB to LSB forms the binary equivalent of 58.
58₁₀ = 111010₂

Hence,
58 in binary is 111010

where,
58₁₀ is the given decimal number,
10 in 58₁₀ represents the base-10 or decimal number system,
111010₂ is the binary equivalent of the decimal 41,
2 in 111010₂ represents the base-2 or binary number system.

Important Notes: (58)10 in Binary
The below are some of the important notes to be remembered while converting the base-10 number 58 into a binary number.

1. The initial or first remainder while performing MOD-2 operation for 58 is a Least Significant Bit (LSB).
2. The last remainder while performing MOD-2 operation for 58 is a Most Significant Bit (MSB).
3. The remainders of MOD-2 operation for 58 should be written from MSB to LSB to form the binary equivalent for the given decimal number (58)10.