Decimal 55 in binary conversion provides the detailed information on what is the binary equivalent of (55)10, and the step-by-step work for how to convert the decimal (base-10) number 55 to its binary (base-2) equivalent.
(55)10 in binary is equal to:
(55)10 = (?)2
Perform successive MOD-2 operation for decimal 55, and mark the initial remainder as LSB and the final remainder as MSB as like the below.
55 MOD-2 | 55 / 2 = 27 | Remainder is 1 → LSB |
27 MOD-2 | 27 / 2 = 13 | Remainder is 1 |
13 MOD-2 | 13 / 2 = 6 | Remainder is 1 |
6 MOD-2 | 6 / 2 = 3 | Remainder is 0 |
3 MOD-2 | 3 / 2 = 1 | Remainder is 1 |
1 MOD-2 | 1 / 2 = 0 | Remainder is 1 → MSB |
Arrange the remainders from MSB to LSB forms the binary equivalent of 55.
5510 = 1101112
Hence,
55 in binary is 110111
where,
55
10 is the given decimal number,
10 in 55
10 represents the base-10 or decimal number system,
110111
2 is the binary equivalent of the decimal 41,
2 in 110111
2 represents the base-2 or binary number system.
Important Notes: (55)10 in Binary
The below are some of the important notes to be remembered while converting the base-10 number 55 into a binary number.
- The initial or first remainder while performing MOD-2 operation for 55 is a Least Significant Bit (LSB).
- The last remainder while performing MOD-2 operation for 55 is a Most Significant Bit (MSB).
- The remainders of MOD-2 operation for 55 should be written from MSB to LSB to form the binary equivalent for the given decimal number (55)10.