Calculators & Converters

    5C1: 5 CHOOSE 1

    nCr - Combination Calculator

    5C1: 5 choose 1 work with steps provide the detailed information about what is the total number of possible combinations occur (nCk) while choosing 1 elements at a time from 8 distinct elements without considering the order of elements.

    nCk of 5C1:
    5 CHOOSE 1 = 5
    where,
    5 is the total number of distinct elements (n),
    1 is the the number of elements drawn or choosen at a time (k),
    5 is the total number of possible combination (C).

    5C1 Points to Remember:

    • 5 CHOOSE 1 can also be denoted as 5C1.
    • Draw 1 out of 5 elements at a time and replace the drawn elements again after the event occurred in the statistical experiments.
    • In 5 possible combinations, AB and BA are not considered as different events.
    • AB and BA considered as a single combination in 5 events.

    For values other than 5 choose 1, use this below tool:
    CHOOSE   

    How-to find nCk: 5 CHOOSE 1?

    5C1 is the type of nCr or nCk problem. The below 5 choose 1 work with steps help users to understand the combinations nCk formula, input parameters and how to find how many possible combinations/events occur while drawing 1 elements at a time from 5 distinct elements without considering the order of elements.

    Solved Example: :
    what is 5 choose 1?

    step 1 Address the input parameters and observe what to be found:
    Input values:
    Total number of distinct elements (n) = 5
    The number of elements drawn at a time (k) = 1

    What to be found:
    Find the total number of possible combinations while choosing 1 elements at a time from 5 distinct elements without considering the order of elements.

    step 2 Find the factorial of 5:
    5! = 1 x 2 x 3 x 4 x 5

    step 3 Find the factorial of 1:
    1! = 1

    step 4 Find the factorial of difference between 5 and 1:
    (5 - 1)! = 4!
    4! = 1 x 2 x 3 x 4

    step 5 Apply the values of 5!, 1! and 4! in the nCk formula:
    nCk = n!/k! (n - k)!
    5C1 =5!/1! x 4!

    =1 x 2 x 3 x 4 x 5/(1) x (1 x 2 x 3 x 4)

    step 6 Simplify the above 5C1 equation:
    =1 x 2 x 3 x 4 x 5/(1) x (1 x 2 x 3 x 4)

    Hence,
    5 choose 1 equals to 5

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