# 4C3: 4 CHOOSE 3 4C3: 4 choose 3 work with steps provide the detailed information about what is the total number of possible combinations occur (nCk) while choosing 3 elements at a time from 8 distinct elements without considering the order of elements.

nCk of 4C3:
4 CHOOSE 3 = 4
where,
4 is the total number of distinct elements (n),
3 is the the number of elements drawn or choosen at a time (k),
4 is the total number of possible combination (C).

4C3 Points to Remember:

• 4 CHOOSE 3 can also be denoted as 4C3.
• Draw 3 out of 4 elements at a time and replace the drawn elements again after the event occurred in the statistical experiments.
• In 4 possible combinations, AB and BA are not considered as different events.
• AB and BA considered as a single combination in 4 events.

For values other than 4 choose 3, use this below tool:
CHOOSE

## How-to find nCk: 4 CHOOSE 3?

4C3 is the type of nCr or nCk problem. The below 4 choose 3 work with steps help users to understand the combinations nCk formula, input parameters and how to find how many possible combinations/events occur while drawing 3 elements at a time from 4 distinct elements without considering the order of elements.

Solved Example: :
what is 4 choose 3?

step 1 Address the input parameters and observe what to be found:
Input values:
Total number of distinct elements (n) = 4
The number of elements drawn at a time (k) = 3

What to be found:
Find the total number of possible combinations while choosing 3 elements at a time from 4 distinct elements without considering the order of elements.

step 2 Find the factorial of 4:
4! = 1 x 2 x 3 x 4

step 3 Find the factorial of 3:
3! = 1 x 2 x 3

step 4 Find the factorial of difference between 4 and 3:
(4 - 3)! = 1!
1! = 1

step 5 Apply the values of 4!, 3! and 1! in the nCk formula:
nCk = n!/k! (n - k)!
4C3 =4!/3! x 1!

=1 x 2 x 3 x 4/(1 x 2 x 3) x (1)

step 6 Simplify the above 4C3 equation:
=1 x 2 x 3 x 4/(1 x 2 x 3) x (1)

= 4/1
= 4/1

4C3 = 4

Hence,
4 choose 3 equals to 4 