getcalc.com's solved example with solution to find what is the probability of getting 5 Heads in 10 coin tosses.
P(A) = 638/1024 = 0.62
for 5 Heads in 10 Coin Flips | ||
---|---|---|
Atleast 5 Heads | Exactly 5 Heads | |
Total Events n(S) | 1024 | 1024 |
Success Events n(A) | 638 | 252 |
Probability P(A) | 0.62 | 0.25 |
The above probability of outcomes applicable to the below questions too.
The ratio of successful events A = 638 to the total number of possible combinations of a sample space S = 1024 is the probability of 5 heads in 10 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 5 heads, if a coin is tossed ten times or 10 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Solution
Step by step workout
step 1 Find the total possible events of sample space S
S = {HHHHHHHHHH, HHHHHHHHHT, HHHHHHHHTH, HHHHHHHHTT, HHHHHHHTHH, HHHHHHHTHT, HHHHHHHTTH, HHHHHHHTTT, HHHHHHTHHH, HHHHHHTHHT, . . . . . . ,TTTTTTTHTT, TTTTTTTTHH, TTTTTTTTHT, TTTTTTTTTH, TTTTTTTTTT}
S = 1024
step 2 Find the expected or successful events A
A = {HHHHHHHHHH, HHHHHHHHHT, HHHHHHHHTH, HHHHHHHHTT, HHHHHHHTHH, HHHHHHHTHT, HHHHHHHTTH, HHHHHHHTTT, HHHHHHTHHH, HHHHHHTHHT, . . . . . . ,TTTTHHHHTH, TTTTHHHTHH, TTTTHHTHHH, TTTTHTHHHH, TTTTTHHHHH}
A = 638
step 3 Find the probability
P(A) = Successful Events/Total Events of Sample Space
= 638/1024
= 0.62
P(A) = 0.62
0.62 is the probability of getting 5 Heads in 10 tosses.