# What is the Probability of 53 Saturdays in a Non-Leap Year?

## How to find probability of 53 Saturdays in a non-leap year?

Users may refer the below detailed information to learn how to find the probability of 53 Saturdays in an ordinary year. The total number of weeks in a non-leap year {365 days = 52 (1/7)} is 52 weeks and one odd day. Since, finding the probability for an odd day to be Saturday is enough to find the probability of getting 53 Saturdays in an ordinary year of a Gregorian calendar.

**Workout**

step 1 Possible events for 1 odd day

The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.

step 2 Probability of 1 Odd day to be Saturday :

The sample space S = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

Expected event of A = {Saturday}

P(A) =

{Saturday}/{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

P(A) = 1/7

P(A) = 0.14

0.14 or 1/7 is probability for 53 Saturdays in a non-leap year.