Decimal 743 in octal conversion provides the detailed information on what is the octal equivalent of (743)10, and the step-by-step work for how to convert the decimal (base-10) number 743 to its octal (base-8) equivalent.
(743)10 in octal is equal to:
(743)10 = (?)8
Perform successive MOD-8 operation for decimal 743, and mark the initial remainder as LSB and the final remainder as MSB as like the below.
MOD-8 of 743 | 743 / 8 = 92 | Remainder is 7 → LSB |
MOD-8 of 92 | 92 / 8 = 11 | Remainder is 4 |
MOD-8 of 11 | 11 / 8 = 1 | Remainder is 3 |
MOD-8 of 1 | 1 / 8 = 0 | Remainder is 1 → MSB |
Arrange the remainders from MSB to LSB forms the octal equivalent of 743.
74310 = 13478
Hence,
743 in octal is 1347
where,
743
10 is the given decimal number,
10 in 743
10 represents the base-10 or decimal number system,
1347
8 is the octal equivalent of the decimal 743,
8 in 1347
8 represents the base-8 or octal number system.
Important Notes: (743)10 in Octal
The below are some of the important notes to be remembered while converting the (base-10) decimal number 743 into a (base-8) octal equivalent.
- The first remainder of MOD-8 of 743 is a Least Significant Bit (LSB).
- The final remainder of MOD-8 of 743 is a Most Significant Bit (MSB).
- The remainders of MOD-8 of 743 should be written from MSB to LSB to form the octal equivalent for the given decimal number (743)10.