645 in Octal

Decimal 645 in octal conversion provides the detailed information on what is the octal equivalent of (645)10, and the step-by-step work for how to convert the decimal (base-10) number 645 to its octal (base-8) equivalent.

(645)10 in octal is equal to:
(645)10 = (?)8

Perform successive MOD-8 operation for decimal 645, and mark the initial remainder as LSB and the final remainder as MSB as like the below.

MOD-8 of 645	645 / 8 = 80	Remainder is 5 → LSB
MOD-8 of 80	80 / 8 = 10	Remainder is 0
MOD-8 of 10	10 / 8 = 1	Remainder is 2
MOD-8 of 1	1 / 8 = 0	Remainder is 1 → MSB

Arrange the remainders from MSB to LSB forms the octal equivalent of 645.
645₁₀ = 1205₈

Hence,
645 in octal is 1205

where,
645₁₀ is the given decimal number,
10 in 645₁₀ represents the base-10 or decimal number system,
1205₈ is the octal equivalent of the decimal 645,
8 in 1205₈ represents the base-8 or octal number system.

Important Notes: (645)10 in Octal
The below are some of the important notes to be remembered while converting the (base-10) decimal number 645 into a (base-8) octal equivalent.

1. The first remainder of MOD-8 of 645 is a Least Significant Bit (LSB).
2. The final remainder of MOD-8 of 645 is a Most Significant Bit (MSB).
3. The remainders of MOD-8 of 645 should be written from MSB to LSB to form the octal equivalent for the given decimal number (645)10.