Decimal 62 in octal conversion provides the detailed information on what is the octal equivalent of (62)10, and the step-by-step work for how to convert the decimal (base-10) number 62 to its octal (base-8) equivalent.
(62)10 in octal is equal to:
(62)10 = (?)8
Perform successive MOD-8 operation for decimal 62, and mark the initial remainder as LSB and the final remainder as MSB as like the below.
MOD-8 of 62 | 62 / 8 = 7 | Remainder is 6 → LSB |
MOD-8 of 7 | 7 / 8 = 0 | Remainder is 7 → MSB |
Arrange the remainders from MSB to LSB forms the octal equivalent of 62.
6210 = 768
Hence,
62 in octal is 76
where,
62
10 is the given decimal number,
10 in 62
10 represents the base-10 or decimal number system,
76
8 is the octal equivalent of the decimal 62,
8 in 76
8 represents the base-8 or octal number system.
Important Notes: (62)10 in Octal
The below are some of the important notes to be remembered while converting the (base-10) decimal number 62 into a (base-8) octal equivalent.
- The first remainder of MOD-8 of 62 is a Least Significant Bit (LSB).
- The final remainder of MOD-8 of 62 is a Most Significant Bit (MSB).
- The remainders of MOD-8 of 62 should be written from MSB to LSB to form the octal equivalent for the given decimal number (62)10.