Decimal 542 in octal conversion provides the detailed information on what is the octal equivalent of (542)10, and the step-by-step work for how to convert the decimal (base-10) number 542 to its octal (base-8) equivalent.
(542)10 in octal is equal to:
(542)10 = (?)8
Perform successive MOD-8 operation for decimal 542, and mark the initial remainder as LSB and the final remainder as MSB as like the below.
MOD-8 of 542 | 542 / 8 = 67 | Remainder is 6 → LSB |
MOD-8 of 67 | 67 / 8 = 8 | Remainder is 3 |
MOD-8 of 8 | 8 / 8 = 1 | Remainder is 0 |
MOD-8 of 1 | 1 / 8 = 0 | Remainder is 1 → MSB |
Arrange the remainders from MSB to LSB forms the octal equivalent of 542.
54210 = 10368
Hence,
542 in octal is 1036
where,
542
10 is the given decimal number,
10 in 542
10 represents the base-10 or decimal number system,
1036
8 is the octal equivalent of the decimal 542,
8 in 1036
8 represents the base-8 or octal number system.
Important Notes: (542)10 in Octal
The below are some of the important notes to be remembered while converting the (base-10) decimal number 542 into a (base-8) octal equivalent.
- The first remainder of MOD-8 of 542 is a Least Significant Bit (LSB).
- The final remainder of MOD-8 of 542 is a Most Significant Bit (MSB).
- The remainders of MOD-8 of 542 should be written from MSB to LSB to form the octal equivalent for the given decimal number (542)10.