47 in Binary

Decimal 47 in binary conversion provides the detailed information on what is the binary equivalent of (47)10, and the step-by-step work for how to convert the decimal (base-10) number 47 to its binary (base-2) equivalent.

(47)10 in binary is equal to:
(47)₁₀ = (?)₂
Perform successive MOD-2 operation for decimal 47, and mark the initial remainder as LSB and the final remainder as MSB as like the below.

47 MOD-2	47 / 2 = 23	Remainder is 1 → LSB
23 MOD-2	23 / 2 = 11	Remainder is 1
11 MOD-2	11 / 2 = 5	Remainder is 1
5 MOD-2	5 / 2 = 2	Remainder is 1
2 MOD-2	2 / 2 = 1	Remainder is 0
1 MOD-2	1 / 2 = 0	Remainder is 1 → MSB

Arrange the remainders from MSB to LSB forms the binary equivalent of 47.
47₁₀ = 101111₂

Hence,
47 in binary is 101111

where,
47₁₀ is the given decimal number,
10 in 47₁₀ represents the base-10 or decimal number system,
101111₂ is the binary equivalent of the decimal 41,
2 in 101111₂ represents the base-2 or binary number system.

Important Notes: (47)10 in Binary
The below are some of the important notes to be remembered while converting the base-10 number 47 into a binary number.

1. The initial or first remainder while performing MOD-2 operation for 47 is a Least Significant Bit (LSB).
2. The last remainder while performing MOD-2 operation for 47 is a Most Significant Bit (MSB).
3. The remainders of MOD-2 operation for 47 should be written from MSB to LSB to form the binary equivalent for the given decimal number (47)10.