# 47 in Binary

Decimal 47 in binary conversion provides the detailed information on what is the binary equivalent of (47)10, and the step-by-step work for how to convert the decimal (base-10) number 47 to its binary (base-2) equivalent.

(47)10 in binary is equal to:
(47)10 = (?)2
Perform successive MOD-2 operation for decimal 47, and mark the initial remainder as LSB and the final remainder as MSB as like the below.

 47 MOD-2 47 / 2 = 23 Remainder is 1 → LSB 23 MOD-2 23 / 2 = 11 Remainder is 1 11 MOD-2 11 / 2 = 5 Remainder is 1 5 MOD-2 5 / 2 = 2 Remainder is 1 2 MOD-2 2 / 2 = 1 Remainder is 0 1 MOD-2 1 / 2 = 0 Remainder is 1 → MSB
Arrange the remainders from MSB to LSB forms the binary equivalent of 47.
4710 = 1011112

Hence,
47 in binary is 101111

where,
4710 is the given decimal number,
10 in 4710 represents the base-10 or decimal number system,
1011112 is the binary equivalent of the decimal 41,
2 in 1011112 represents the base-2 or binary number system.

Important Notes: (47)10 in Binary
The below are some of the important notes to be remembered while converting the base-10 number 47 into a binary number.
1. The initial or first remainder while performing MOD-2 operation for 47 is a Least Significant Bit (LSB).
2. The last remainder while performing MOD-2 operation for 47 is a Most Significant Bit (MSB).
3. The remainders of MOD-2 operation for 47 should be written from MSB to LSB to form the binary equivalent for the given decimal number (47)10.

For decimal values other than 47, use this below tool: 