40 in Octal

Decimal 40 in octal conversion provides the detailed information on what is the octal equivalent of (40)10, and the step-by-step work for how to convert the decimal (base-10) number 40 to its octal (base-8) equivalent.

(40)10 in octal is equal to:
(40)10 = (?)8

Perform successive MOD-8 operation for decimal 40, and mark the initial remainder as LSB and the final remainder as MSB as like the below.

MOD-8 of 40	40 / 8 = 5	Remainder is 0 → LSB
MOD-8 of 5	5 / 8 = 0	Remainder is 5 → MSB

Arrange the remainders from MSB to LSB forms the octal equivalent of 40.
40₁₀ = 50₈

Hence,
40 in octal is 50

where,
40₁₀ is the given decimal number,
10 in 40₁₀ represents the base-10 or decimal number system,
50₈ is the octal equivalent of the decimal 40,
8 in 50₈ represents the base-8 or octal number system.

Important Notes: (40)10 in Octal
The below are some of the important notes to be remembered while converting the (base-10) decimal number 40 into a (base-8) octal equivalent.

1. The first remainder of MOD-8 of 40 is a Least Significant Bit (LSB).
2. The final remainder of MOD-8 of 40 is a Most Significant Bit (MSB).
3. The remainders of MOD-8 of 40 should be written from MSB to LSB to form the octal equivalent for the given decimal number (40)10.