Decimal 263 in octal conversion provides the detailed information on what is the octal equivalent of (263)10, and the step-by-step work for how to convert the decimal (base-10) number 263 to its octal (base-8) equivalent.
(263)10 in octal is equal to:
(263)10 = (?)8
Perform successive MOD-8 operation for decimal 263, and mark the initial remainder as LSB and the final remainder as MSB as like the below.
MOD-8 of 263 | 263 / 8 = 32 | Remainder is 7 → LSB |
MOD-8 of 32 | 32 / 8 = 4 | Remainder is 0 |
MOD-8 of 4 | 4 / 8 = 0 | Remainder is 4 → MSB |
Arrange the remainders from MSB to LSB forms the octal equivalent of 263.
26310 = 4078
Hence,
263 in octal is 407
where,
263
10 is the given decimal number,
10 in 263
10 represents the base-10 or decimal number system,
407
8 is the octal equivalent of the decimal 263,
8 in 407
8 represents the base-8 or octal number system.
Important Notes: (263)10 in Octal
The below are some of the important notes to be remembered while converting the (base-10) decimal number 263 into a (base-8) octal equivalent.
- The first remainder of MOD-8 of 263 is a Least Significant Bit (LSB).
- The final remainder of MOD-8 of 263 is a Most Significant Bit (MSB).
- The remainders of MOD-8 of 263 should be written from MSB to LSB to form the octal equivalent for the given decimal number (263)10.