Standard Error (SE) of Mean & Proportion Calculator
Calculation summary & work with steps for sample size n1 = 50, n2 = 60, population proportion P1 = 0.35 & P2 = 0.45 to estimate the standard error of difference between two sample proportions. The below is the calculation summary for SE of (p1 - p2) for sample size n1 = 50 & n2 = 60 using the p values P1 = 0.35 & P2 = 0.45.
Calculation Summary | |
---|---|
Population proportion (P1) | 0.35 |
Population proportion (P2) | 0.45 |
Sample size (n1) | 50 |
Sample size (n2) | 60 |
SE of (p1 - p2) | 0.0933 |
SE of (p1 - p2) Work with Steps for n1 = 50 & n2 = 60
The below is the example work with step by step calculation shows how to estimate the standard error of difference between two sample proportions for sample size n1 = 50 & n2 = 60 and the population proportions P1 = 0.35 & P2 = 0.45 to help grade school students to solve the similar SE of (p1 - p2) worksheet problems efficiently.
Workout :
step 1 Address the formula, input parameters and values
Input parameters & values
Population Proportion P1 = 0.35
Population Proportion P2 = 0.45
Sample Size n1 = 50
Sample Size n2 = 60
Formula
SE(p1-p2) = √
step 2 Find Q from P Values
Q1 = 1 - P1 = 1 - 0.35
Q1 = 0.65
Q2 = 1 - P2 = 1 - 0.45
Q2 = 0.55
step 3 Apply the values in below formula
= √
= √
step 4 Simplify the above equation
= √0.0046 + 0.0041
= √0.0087
= 0.0933
0.0933 is the standard error for difference between two sample proprotions.
step 1 Address the formula, input parameters and values
Input parameters & values
Population Proportion P1 = 0.35
Population Proportion P2 = 0.45
Sample Size n1 = 50
Sample Size n2 = 60
Formula
SE(p1-p2) = √
P1Q1/n1+P2Q2/n2
step 2 Find Q from P Values
Q1 = 1 - P1 = 1 - 0.35
Q1 = 0.65
Q2 = 1 - P2 = 1 - 0.45
Q2 = 0.55
step 3 Apply the values in below formula
= √
(0.35 x 0.65)/50+(0.45 x 0.55)/60
= √
0.2275/50+0.2475/60
step 4 Simplify the above equation
= √0.0046 + 0.0041
= √0.0087
= 0.0933
0.0933 is the standard error for difference between two sample proprotions.
