Sum of First 25 Positive Integers Divisible by 3

3 + 6 + 9 + 12 + 15 + 18 + 21 + . . . . + 75 = 975
It's difficult to find the sum of first 25 positive integers divisible by 3 without knowing what algebraic function to use. This online Arithmetic Progression calculator, formula and step by step solution using simple method helps you to learn how to quickly find the sum of first 25 positive integers divisible by 3.

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The below workout with step by step solution using easiest method, shows how to find the sum of first 25 positive integers divisible by 3 by applying arithmetic progression.
step 1 Input Parameters and values:
The number series 3, 6, 9, 12, 15, 18, 21, . . . . , 75.
The first term a = 3
The common difference d = 3
Total number of terms n = 25

step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + T_n)
= 25/2 x (3 + 75)
= (25 x 78)/ 2
= 1950/2
3 + 6 + 9 + 12 + 15 + 18 + 21 + . . . . + 75 = 975

Therefore,
975 is the sum of first 25 positive integers divisible by 3.

Sum of First 25 Positive Integers Divisible by 3

Step-by-Step Solution: Sum of First 25 Positive Integers Divisible by 3

First 25 Numbers Divisible by 3