(41)8 = (?)10. Octal 41 to decimal decimal conversion provides the detailed information on what is the decimal equivalent of the octal 41 and the step-by-step work for how to convert (41)8 into corresponding (base-10) decimal equivalent manually.

__(41) _{8} in decimal is equal to:__

41

0o41 = 33

Hence,

the decimal equivalent of octal number (41)8 is (33)10.

41

8 in 41

33 is the decimal equivalent of octal number 41,

10 in 33

The below are some of the important notes to be remembered while converting the (base-8) octal number 41 into a (base-10) decimal equivalent.

- The right most digit in the given base-8 number 41 is a Least Significant Digit (LSD).
- The left most digit in the given base-8 number 41 is a Most Significant Digit (MSD).
- The LSD of 41 should be multiplied with 8
^{0}. - The MSD of 41 should be multiplied with 8
^{(no. of digits - 1)}.

The below step-by-step solution shows how to convert (41)8 into decimal equivalent. To find the decimal equivalent of (41)8, multiply 8^{0} with the right most digit, 8^{1} with the left subsequent digit and so on until the left most digit of the given octal number 41. The sum of all individual products is the decimal equivalent of octal 41.

__Solved Example:__

Convert (41)8 into decimal equivalent.

step 1 Observe the input parameters, values and what to be found.

Input values:

Octal Number = 41_{8}

What to be found:

What is the decimal equivalent of (41)8?

step 2 Multiply 8^{0} with the right most digit, 8^{1} with the left subsequent digit and so on until the left most digit of the given octal number 41. Therefore, arrange the given decimal number 41 in the expression form as like the below:

= (4 x 8^{1}) + (1 x 8^{0})

step 3 Resolve the powers of 8 in the above equation:

= (4 x 8) + (1 x 1)

step 3 Simplify the above equation further:

= 32 + 1

= 33

(41)_{2} = (33)_{10}

Therefore,

33 is the decimal equivalent of octal number (41)8