What is the Sum of First 130 Positive Integers which are Divisible by 3?
How to Find the Sum of First 130 Positive Integers which are Divisible by 3?
The below workout with step by step calculation shows how to find what is the sum of first 130 positive integers which are divisible by 3 by applying arithmetic progression. It's one of the easiest methods to quickly find the sum of given number series.
step 1 Input Parameters and values:
The number series 3, 6, 9, 12, 15, 18, 21, . . . . , 390.
The first term a = 3
The common difference d = 3
Total number of terms n = 130
step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 130/2 x (3 + 390)
= (130 x 393)/ 2
= 51090/2
3 + 6 + 9 + 12 + 15 + 18 + 21 + . . . . + 390 = 25545
Therefore, 25545 is the sum of first 130 positive integers which are divisible by 3.