# What is the Sum of First 100 Positive Integers which are Divisible by 6?

## How to Find the Sum of First 100 Positive Integers which are Divisible by 6?

The below workout with step by step calculation shows how to find what is the sum of first 100 positive integers which are divisible by 6 by applying arithmetic progression. It's one of the easiest methods to quickly find the sum of given number series.

step 1 Address the formula, input parameters & values.

Input parameters & values:

The number series 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . . . , 600.

The first term a = 6

The common difference d = 6

Total number of terms n = 100

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + T_{n})

= 100/2 x (6 + 600)

= (100 x 606)/ 2

= 60600/2

6 + 12 + 18 + 24 + 30 + 36 + 42 + 48 + 54 + 60 + . . . . + 600 = 30300

Therefore, **30300** is the sum of first 100 positive integers which are divisible by 6.