Find what is the Volume & Surface Area of Pyramid for L = 90, H = 30 & W = 75

Calculation Summary | |
---|---|
Length | 90 in |
Width | 75 in |
Height | 30 in |
Volume V | 67500 in³ |
Surface Area | 15128.354 in² |
Lateral Area | 8378.354 in² |
Work with Steps to find Volume & Surface Area of Pyramid for L = 90, H = 30 & W = 75
Question:
The length of pyramid is 90 inches, width is 75 inches and height is 30 inches, find what is the volume, surface area and lateral surface of the pyramid?
Workout :The length of pyramid is 90 inches, width is 75 inches and height is 30 inches, find what is the volume, surface area and lateral surface of the pyramid?
step 1 Address the formula input parmaeter & values
Length = 90 in
Height = 30 in
Width = 75 in
step 2 Find Pyramid Volume using length, height and width values
Volume V = lwh/3
=90 x 75 x 30/3in³
= 202500/3in³
Volume v = 67500 in³
step 3 Find Surface Area using length, height and width values
Surface Area = lw + l √(w/2)² + h² + w √(l/2)² + h²
= (90 x 75) + 90 √(75/2)² + 30² + 75 √(90/2)² + 30² in²
= 6750 + 90 √(37.5)² + 30² + 75 √(45)² + 30² in²
= 6750 + 90 √(1406.25) + 900 + 75 √(2025) + 900 in²
= 6750 + 90 √2306.25 + 75 √2925 in²
= 6750 + (90 x 48.0234) + (75 x 54.0833) in²
= 8100 + 4322.1089 + 4056.2452 in²
Surface Area = 15128.354 in²
step 4 Find Lateral Area using length, height and width values
Lateral Area = l √(w/2)² + h² + w √(l/2)² + h²
= 90 √(75/2)² + 30² + 75 √(90/2)² + 30² in²
= 90 √(37.5)² + 30² + 75 √(45)² + 30² in²
= 90 √(1406.25) + 900 + 75 √(2025) + 900 in²
= 90 √2306.25 + 75 √2925 in²
= (90 x 48.0234) + (75 x 54.0833) in²
= 4322.1089 + 4056.2452 in²
Lateral Area = 8378.354 in²
