# Find what is the Volume & Surface Area of Pyramid for L = 9, H = 6 & W = 7 The volume of pyramid is 126 and surface area is 178.016 for the given length as 9, height as 6 and width as 7, refer the calculation summary and work with steps for detailed explanation.
Calculation Summary
Length9 in
Width7 in
Height6 in
Volume V126 in³
Surface Area 178.016 in²
Lateral Area 115.016 in²

## Work with Steps to find Volume & Surface Area of Pyramid for L = 9, H = 6 & W = 7

Question:
The length, width & height of a pyramid measured as 9 inches, 7 inches and 6 inches respectively, find what is the volume, surface area and lateral surface of the pyramid?
Workout :
step 1 Address the formula input parmaeter & values
Length = 9 in
Height = 6 in
Width = 7 in

step 2 Find Pyramid Volume using length, height and width values
Volume V = lwh/3
=9 x 7 x 6/3in³
= 378/3in³
Volume v = 126 in³

step 3 Find Surface Area using length, height and width values
Surface Area = lw + l √(w/2)² + h² + w √(l/2)² + h²

= (9 x 7) + 9 √(7/2)² + 6² + 7 √(9/2)² + 6² in²

= 63 + 9 √(3.5)² + 6² + 7 √(4.5)² + 6² in²

= 63 + 9 √(12.25) + 36 + 7 √(20.25) + 36 in²

= 63 + 9 √48.25 + 7 √56.25 in²
= 63 + (9 x 6.9462) + (7 x 7.5) in²
= 81 + 62.516 + 52.5 in²
Surface Area = 178.016 in²

step 4 Find Lateral Area using length, height and width values
Lateral Area = l √(w/2)² + h² + w √(l/2)² + h²

= 9 √(7/2)² + 6² + 7 √(9/2)² + 6² in²

= 9 √(3.5)² + 6² + 7 √(4.5)² + 6² in²

= 9 √(12.25) + 36 + 7 √(20.25) + 36 in²

= 9 √48.25 + 7 √56.25 in²
= (9 x 6.9462) + (7 x 7.5) in²
= 62.516 + 52.5 in²
Lateral Area = 115.016 in² 