Find what is the Volume & Surface Area of Pyramid for L = 9, H = 6 & W = 7
The volume of pyramid is 126 and surface area is 178.016 for the given length as 9, height as 6 and width as 7, refer the calculation summary and work with steps for detailed explanation.| Calculation Summary | |
|---|---|
| Length | 9 in |
| Width | 7 in |
| Height | 6 in |
| Volume V | 126 in³ |
| Surface Area | 178.016 in² |
| Lateral Area | 115.016 in² |
Work with Steps to find Volume & Surface Area of Pyramid for L = 9, H = 6 & W = 7
Question:
The length, width & height of a pyramid measured as 9 inches, 7 inches and 6 inches respectively, find what is the volume, surface area and lateral surface of the pyramid?
Workout :The length, width & height of a pyramid measured as 9 inches, 7 inches and 6 inches respectively, find what is the volume, surface area and lateral surface of the pyramid?
step 1 Address the formula input parmaeter & values
Length = 9 in
Height = 6 in
Width = 7 in
step 2 Find Pyramid Volume using length, height and width values
Volume V = lwh/3
=9 x 7 x 6/3in³
= 378/3in³
Volume v = 126 in³
step 3 Find Surface Area using length, height and width values
Surface Area = lw + l √(w/2)² + h² + w √(l/2)² + h²
= (9 x 7) + 9 √(7/2)² + 6² + 7 √(9/2)² + 6² in²
= 63 + 9 √(3.5)² + 6² + 7 √(4.5)² + 6² in²
= 63 + 9 √(12.25) + 36 + 7 √(20.25) + 36 in²
= 63 + 9 √48.25 + 7 √56.25 in²
= 63 + (9 x 6.9462) + (7 x 7.5) in²
= 81 + 62.516 + 52.5 in²
Surface Area = 178.016 in²
step 4 Find Lateral Area using length, height and width values
Lateral Area = l √(w/2)² + h² + w √(l/2)² + h²
= 9 √(7/2)² + 6² + 7 √(9/2)² + 6² in²
= 9 √(3.5)² + 6² + 7 √(4.5)² + 6² in²
= 9 √(12.25) + 36 + 7 √(20.25) + 36 in²
= 9 √48.25 + 7 √56.25 in²
= (9 x 6.9462) + (7 x 7.5) in²
= 62.516 + 52.5 in²
Lateral Area = 115.016 in²
