# σ = 0.75, n = 560 & 99% Confidence Level - Margin of Error Example

Example problem workout with steps & calculation summary for accepted margin of error calculated from *population standard deviation* σ = 0.75, *sample size* n = 560 & 99% confidence level in statistical surveys or experiments.

Calculation Summary | |
---|---|

Standard Deviation (σ) | 0.75 |

Sample Size (n) | 560 |

Confidence Level | 99% |

MOE | 8.16% |

## Work with Steps for σ = 0.75 n = 560 & 99% Confidence Level

__Question:__

A survey was conducted among 560 students to know the interest of reducing the class hours, what is the acceptable margin of error included in this survey to make the survey results statistically significant at 99% confidence level. The deviation of interest of students is 0.75.

__Workout :__

step 1 Address the formula input parameters and values

Standard Deviation (σ) = 0.75

Sample Size (n) = 560

Z value for 99% confidence level = 2.575

MOE = Z σ√n

step 2 Substitute σ , n & Z value in the below margin of error formula

MOE = 2.575 x 0.75√560

step 3 Solve the above expression

MOE = 2.575 x 0.75/23.6643

= 2.575 x 0.0317

= 0.0816 x 100

= 8.16 %

Thus 8.16 % is the Margin of error calculated from σ = 0.75, n = 560 & 99% confidence level.

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